Question

If one of the zeroes of the p(x)=2x^2+px+4=0 is 2, find the other root and also find the value of p.

Answer 1

p(2)=0
2(2)^2+2p+4=0
2p=-12
p= -6
so p(x)= 2x^2-6x+4=0
(x-2)(x-1)=0
x=2 or x=1

Answer 2

x= 2 or x= 1.

l think u will get it..