Question

if one of the zeroes of the polynomial 3x²-8x+2k+1 is 7 times the other, find the zeroes and the value of k​

Answer 1

I hope the attachment answer will help you:)

Answer 2

Answer:

3x ^ 2 - 8x + 2k + 1a = 3 , b = - 8, c = 2k + 1

suppose the zeroes of the equation are a and B. by the given condition alpha = 7beta as we know, a+B=-b/a

7beta + beta = - (- 8) / 3

8beta = 8/3

B=8/3x1/8=1/3

aß=c/a

7beta * beta = 2k + 1/3

7 * 1 / 3 * 1 / 3 = 2k + 1/3

7/9 = 2k + 1/3

21/9 = 2k + 1

21/9 - 1 = 2k

12/9 = 2k

4/3 = 2k

4/6 = k

2/3 = k

Step-by-step explanation:

This is the answer Hope it helps you