Question

if one of the zeroes of the polynomial (a2+9)x2+13x+6a is the reciprocal of the other then find the value of a

Answer 1

Answer:

Hello mate ✌️

Step-by-step explanation:

hope it will be helpful to you ✌️

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Answer 2

Answer:

a=3

Step-by-step explanation:

Given:

          (i) let us consider one of the zeroes of the polynomial as  'k'

            hence, the other zero = 1/k (reciprocal of k)

           (ii) p(x) = (a2+9)x + 13x + 6a ; A=a2+9; B=13; C=6a

To find: value of a

Solution:

We know that, k*1/k = C/A (relationship between the coefficients and zeroes of a polynomial)

==> 1= 6a/ (a2+9)

or a2+9= 6a

or a2-6a+9=0

or a2-3a-3a+9=0

or a(a-3)-3(a-3)=0

or (a-3)(a-3)=0

or a=3

Therefore, the value of a is 3