Question

if one of the zeroes of the polynomial (k-1)x^2=kx+1 is -3. find the value of k

Answer 1

plz see the screenshot

Answer 2

Answer:

k = -8/3

Step-by-step explanation:

as -3 is a zero .. x=-3

$x^{2}$ = kx +1

=>  $x^{2}$ - kx -1 =0

=>  $-3^{2}$ - (-3k) -1 =0

=>  $-3^{2}$ + 3k - 1 = 0

=>  9 +3k - 1 =0

=>  8 +3k =0

=> k = -8/3