If one of the zeroes of the polynomial p(x)= 6x2 –x –k is 2 3 then, find the value of k.
Answers
Answered by
4
Answer:
The given quadratic equation is 6x2 − x − k = 0. Thus, the value of k is 2.
Answered by
3
Answer:
6x
2
−x−x=0
if x =
2
3
is a root then,it must satisfy equation
Putx=
2
3
6(
2
3
)
2
−
2
3
−k=0
3×
2
9
−
2
3
−k=0
k=
2
27
−
2
3
=
2
24
=12
k=12
Similar questions