If one of the zeroes of the polynomial p(x)= 6x2 –x –k is 2/ 3 then, find the value of k.
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Put the value of x.
Answer:
p(x) = 6×2-x-k
p(2/3)= 12-x-k
= 12-2/3-k
k = 12-(2/3)
= 34/3
Hence, the value of k is 34/3.
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