Question

If one of the zeroes of the polynomial p(x)=x2-x+k is 2.Then find the value of k

Answer 1

Answer:

What is the value of the Polynomial, P(x)= x2

-5x -6 at x=2 ?What is the value of the Polynomial, P(x)= x2

-5x -6 at x=2 ?What is the value of the Polynomial, P(x)= x2

-5x -6 at x=2 ?

Explanation:

What is the value of the Polynomial, P(x)= x2

-5x -6 at x=2 ?

Answer 2

Answer:

One of the zeroes of p(x) is 2, then the value of k is -2.

Explanation:

The query asks us to discover the fee of ok in the polynomial p(x) = x^2 - x + okay given that one of the zeroes of the polynomial is 2.

A zero of a polynomial is a fee of x that makes the polynomial equal to zero. In different words, if a is a zero of the polynomial p(x), then p(a) = 0.

In this case, we are given that two is a zero of p(x), so we understand that p(2) = zero Substituting x = two into the polynomial, we get:

If two is a zero of the polynomial p(x) = $x^2$ - x + k, then we be aware of that p(2) = 0.

Therefore, we can alternative x = two into the polynomial and set it equal to zero:

             p(2) = $2^2$ - two + ok

             p(2) = 0

Simplifying this equation, we get:

             4 - two + ok = 0

             2 + okay = 0

             k = -2

Therefore, if one of the zeroes of p(x) = $x^2$ - x + ok is 2, then the cost of okay is -2.

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