if one of the zeroes of the polynomial P(x)=xsquare—x+k is 2 ,then the value of k is
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As one of the zeroes is 2
Therefore, x=2
P(2)= 2square - 2 +k
4-2+k=0
2+k=0
k= -2 (answer)
Therefore, x=2
P(2)= 2square - 2 +k
4-2+k=0
2+k=0
k= -2 (answer)
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