Question

If one of the zeroes of the polynomial p (x)+xsquare -x+ k is 2 then the volueof k is

Answer 1

Answer:

k=2

Step-by-step explanation:

p(x)=x^2 - x+ k= 2

p(1) = 1^2 - 1 + k = 2

p(1) = 1 - 1 + k =2

p(1) = k = 2

k=2

Answer 2

Step-by-step explanation:

Given,

p(x)=x²-x+k

"2" is a zero of p(x)

if 2 is a zero of p(x), then we can say that

2²-2+k=0 [by substituting 2 in the place of x]

then,

4-2+k=0

2+k=0

k= -2

now, yhe polynomial p(x)=x²-x-2