Question

if one of the zeroes of the polynomial x^3+9x^2+bx+c is -1 . then prove that the product of other two zeros is b-a+ 1 .
find the value of a and b
​

Answer 1

Answer:

In △ABC AB=AC

⇒∠B=∠C (Angles opposite to equal sides are equal)

Now using angle sum property

∠A+∠B+∠C=180

∘

⇒80

∘

+∠C+∠C=180

∘

⇒2∠C=180

∘

−80

∘

⇒∠C=

2

100

∘

=50

∘

now ∠C+∠x=180

∘

(Angles made on straight line (AC) are supplementary)

⇒50

∘

+∠x=180

∘

⇒∠x=180

∘

−50

∘

=130

∘

@ARSH

♥️♥️

⚠️insta@_arsh_deep_29⚠️