Question

If one of the zeroes of the polynomial -x cube-6+7x is 1, find the other zeroes

Answer 1

your equation is $- x^3 + 7 x - 6 = 0$
Divide it by $x - 1$
$\frac{ - x ^ 3 + 7x - 6}{x - 1} = -x^2 -x + 6 = -(x+3)(x-2)$
so other roots x = -3,2