Question

If one of the zeroes of the quadra
polynomial (k – 1) x square + kx + 1 is -3, then the
value of k is​

Answer 1

Given that -3 is a zero of f(x)

so, f(-3)=0

(-3)^2+k(-3)+1=0

9-3k+1=0

10-3k=0

10=3k

k=10/3

hope it helps

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8. ......

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .