Question

If one of the zeroes of the quadratic equation (k+1)x^2+kx+1 is 2,then find the value of k?

Answer 1

Given one zero of eqn. 2.
Substituting the zero in eqn, 
(k+1)2^2 + k2 + 1 = 0
(k+1)4 +2k + 1 = 0
4k + 4 + 2k + 1 = 0
6k + 5 = 0 
or k = -5/6 (Ans).
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Answer 2

given  equation,
( k+1)x² + k x + 1
zero of the equation is 2
⇒( k+1)(2)² + k(2) +1 = 0
⇒( k+1)4 +2k +1 =0
⇒4k+4+2k+1 =0
⇒6k+5= 0
⇒  6k = -5
⇒ k = -5/6