If one of the zeroes of the quadratic polynomial ( – 1) 2 + + 1 is −3, then the value of k is
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here is the answer:-
Given −3 is the zero of the polynomial (k−1) x2 +kx+1
So −3 must satisfy the equation (k−1)x2+kx+1=0
⟹(k−1)(−3)2
+k(−3)+1=0
⟹9(k−1)−3k+1=0
⟹9k−9−3k+1=0
⟹6k=8
⟹k=3upon4
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