If one of the zeroes of the quadratic polynomial 14x^2-42k^2x-9 is negative of the other find the valu of k
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Heya !!!
Let alpha be a one zero of the given polynomial.
Other zero will be (-Alpha)
P(X) = 14X² - 42K² - 9
Here,
A = 14 , B = -42K² and C = -9
Sum of zeroes = -B/A
Alpha + (-Alpha) = -(-42K²)/14
0 = 42K²/14
K² = 0
K = 0
★ HOPE IT WILL HELP YOU ★
Let alpha be a one zero of the given polynomial.
Other zero will be (-Alpha)
P(X) = 14X² - 42K² - 9
Here,
A = 14 , B = -42K² and C = -9
Sum of zeroes = -B/A
Alpha + (-Alpha) = -(-42K²)/14
0 = 42K²/14
K² = 0
K = 0
★ HOPE IT WILL HELP YOU ★
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