If one of the zeroes of the quadratic polynomial ax^2 +ax +1 is -3, then the valuq of a is
(a) -2/3
(b)2/3
(c)4/5
(d) 2
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Answer: -1/6
we know the value of x since it is given that the zero of it is -3, so we subsititute the value of x
ax² + ax + 1 = 0
a(-3)² + a(-3) + 1 = 0
9a + (-3a) + 1 = 0
6a = (-1)
a = -1/6
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