if one of the zeroes of the quadratic polynomial f(x)=4x²-8kx-9 is equal in magnitude but opposite in sign of the other, then find the value of k.
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Hlww dear ........
Here is ur answer.......
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Here is ur answer.......
Hope it is helpful✌✌
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Answer :-
→ k = 0 .
Step-by-step explanation :- ----
It is given that,
→ One zeros of the given polynomial is negative of the other .
Let one zero of the given polynomial be x .
Then, the other zero is -x .
•°• Sum of zeros = x + ( - x ) = 0 .
But, Sum of zeros = -( coefficient of x )/( coefficient of x² ) = - ( -8k )/4 .
==> 2k = 0 .
==> k = 0/2 .
•°• k = 0 .
Hence, it is solved.
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