Question

If one of the zeroes of the quadratic polynomial (k-1)x^2+k×x+1 is -3 then value of k is

Answer 1

Answer:

Step-by-step explanation:

(k - 1)x² + kx + 1.

Since one of the zeroes is -3,so when we substitute -3 in the polynomial we get 0

(k - 1) (-3)² + k (-3) + 1 = 0

=> 9k - 9 - 3k + 1 = 0

=> 6k - 8 = 0

=> 6k = 8

=> k = 8/6 = 4/3

Thus the value of k = 4/3.