Question

If one of the zeroes of the quadratic polynomial(k-1)x^2+kx+1 is -3,then the value of k is

Answer 1

if x=-3

(k-1)9-3k+1=0

9k-9-3k+1=0

6k-8=0

k=8/6=4/3

HOPE IT'S HELPFUL....

Answer 2

Step-by-step explanation:

We substitute the zero value of the equation

Now we get,,

9k²-18k+9+3k+1=0

Taking the constant terms to the other side we get,

9k²-15k=-10

Now we bring - 10 to the other side and factorisation