Question

) If one of the zeroes of the quadratic polynomial (k-1)x^2 + kx + 1 is -3, then the value of k is: FAST ANS

Answer 1

Answer:

4/3 = k

Step-by-step explanation:

put x = -3 and solve the equation

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Answer 2

ANSWER:

GIVEN:

• P(x) = (k-1)x²+Kx+1
• One zero = (-3)

TO FIND:

• Value of'k'.

SOLUTION:

P(x) = (k-1)x²+Kx+1

If we put x = (-3) in P(x) then we will get the remainder = 0.

Substituting x = (-3) in P(x) We get;

=> (k-1)(-3)²+k(-3)+1 = 0

=> 9(k-1)-3k+1 = 0

=> 9k-9-3k+1 = 0

=> 6k-8 = 0

=> 6k = 8

=> k = 8/6

=> k = 4/3

Value of k = 4/3

NOTE:

Some important formulas:

=> Sum of zeros (α+β) = -(Coefficient of x)/Coefficient of x²

=> Product of zeros (αβ) = Constant term/ Coefficient of x²