Question

if one of the zeroes of the quadratic polynomial (k-1) x^2+kx+1 is '-3'then the value of'k'is​

Answer 1

Put x = - 3 in the given quadratic equation
(k - 1)9 - 3k + 1 = 0
9k - 9 - 3k + 1 = 0
6k - 8 = 0
k = 4/3

Answer 2

Step-by-step explanation:

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➥ Ur answer :

$One \: of \: the \: zeroes \: of \: the \: Polynomial \: is \: - 3 \\ so \: \\ (k - 1) {( - 3)}^{2} + k( - 3) + 1 = 0 \\ 9k - 9 - 3k + 1 = 0 \\ 6k = 8 \\ k = \frac{4}{3}$

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