Question

. If one of the zeroes of the quadratic polynomial (k – 1)x2(square) + kx + 1 is –3, then the value of k is

Answer 1

given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3

so when we substitute -3 in the polynomial ,we get 0

→(k-1)(-3)²+k(-3)+1=0

→9k-9-3k+1=0

→6k-8=0

→k=8/6=4/3

Answer 2

hi mate

given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3

so when we substitute -3 in the polynomial ,we get 0

→(k-1)(-3)²+k(-3)+1=0

→9k-9-3k+1=0

→6k-8=0

→k=8/6=4/3

I hope this will help u ;)

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