If one of the zeroes of the quadratic polynomial (k–1) x2 + k x + 1 is –3, then the value of k is
(A) 4/3 (B) –43 (C) 2/3 (D)–2/3
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If one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3then find the value of k
Ask for details Follow Report by Keeshapinto 03.06.2017
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dhathri123
dhathri123 Ace
Hi friend,
given one of the zeros of quadratic polynomial (k-1)x2+kx+1 is -3
so when we substitute -3 in the polynomial ,we get 0
→(k-1)(-3)²+k(-3)+1=0
→9k-9-3k+1=0
→6k-8=0
→k=8/6=4/3
I hope this will help u ;)
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I hope it's help you................
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