If one of the zeroes of the
quadratic polynomial (k-1) x2 + k
X + 1 is 2, then the value of k is:
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Answer:
Given : One of the zeros of quadratic polynomial (k−1)x
2
+kx+1 is −3
To find : Value of k
Solution : As −3 is one of the zeros of quadratic polynomial (k−1)x
2
+kx+1
⇒ When we substitute −3 in the polynomial , we get 0
⟹(k−1)(−3)
2
+k(−3)+1=0
⟹9k−9−3k+1=0
⟹6k−8=0
or k=
6
8
=
3
4
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