Question

If one of the zeroes of the quadratic polynomial (k-1)x2

+ kx +1 is -3, then the value of k is

(a) (b) - (c) (d)-
​

Answer 1

Answer:

p(x) = (k-1)×2 + kx +1

then

p(-3) = (k-1)×2 + k×(-3) + 1

for zeroes of a polynomial

p(x)=0

0 = (k-1)×2 -3k +1

0= 2k -2 -3k +1

0 = -1 -k

1 = -k

so,

k = -1 answer

Answer 2

k = -1

Hope it helps.....