Question

If one of the zeroes of the quadratic polynomial (k – 1)x2 + kx + 1 is –3, then the value of k is ??
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Answer 1

Step-by-step explanation:

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Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

If one of the zeroes of the quadratic polynomial (k-1)x² + kx + 1 is -3.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The value of k.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

$\leadsto\sf{f(x)=(k-1)x^{2} +kx+1}\\\leadsto\sf{f(-3)=0}$

A/q

$\longrightarrow\sf{(k-1)(-3)^{2} +k(-3)+1=0}\\\\\longrightarrow\sf{(k-1)(9)+(-3k)+1=0}\\\\\longrightarrow\sf{9k-9-3k+1=0}\\\\\longrightarrow\sf{9k-3k-8=0}\\\\\longrightarrow\sf{6k=8}\\\\\longrightarrow\sf{k=\cancel{\dfrac{8}{6} }}\\\\\\\longrightarrow\sf{\pink{k=\dfrac{4}{3} }}$

Thus;

The value of k is 4/3 .

$\boxed{\begin{minipage}{6cm} \underline{FORMULA OF QUADRATIC} \\ \\ \sf{We \:can \:compared\: polynomial \:ax^{2} +bx+c } \\ \\ \sf{x=\dfrac{-b\pm\sqrt{b^{2}-4ac } }{2a}} \end{minipage}}$