Question

If one of the zeroes of the quadratic polynomial ( K-1 ) × x2+kx+1 is -3 the value of k is​

Answer 1

Pls mark as brainliest answer

Answer 2

Answer:

$\huge \bigstar \: \huge \boxed{k = \frac{4}{3} } \: \bigstar$

Step-by-step explanation:

→ Given :–

• One of the zero of the Quadratic Polynomial (k-1)x²+kx+1 is -3.

→ To Find :–

• The Value of k.

→ Solution :–

p(x)=(k-1)x²+kx+1=0

=> Put x=(-3) in this Quadratic Polynomial:

→ p(-3)=(k-1)(-3)²+k(-3)+1=0

→ (k-1)(9)-3k+1=0

→ 9k-9-3k+1=0

→ 6k-8=0

→ 6k=8

$\implies k = \frac{8}{6}$

$\star \: \boxed{k = \frac{4}{3} } \: \star$