If one of the zeroes of the quadratic polynomial (k – 1 )x2 + kx + 1 is -3 ,then the value of k is
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Explanation:
If one of the zeroes of the quadratic polynomial (k – 1 )x2 + kx + 1 is -3 ,then the value of k is =0
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sol : we have , p(x) = ( k - 1 )x2 + kx +1
p( -3 ) =o
= ( k - 1 ) ( -3 )2 + k ( -3 ) + 1 =0
= ( k - 1 ) ( -9 ) + ( -3k ) + 1 = 0
= -9k +9 -3k +1 =0
= -12k + 10 = 0
= 12k / 10
k= 5/6
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