Question

if one of the zeroes of the quadratic polynomial (k-1) x2 +kx + 1 is -3 then the value of k is
(a) 4/3
(b) -4/3
(c) 2/3
(d) -2/3​

Answer 1

$♕ \: \: \large{\rm{{\underline{\underline{\red{S}\purple{O}\pink{LU}\orange{TI}\green{ON}}}}}} \: \: ♕$

FORMULA TO BE IMPLEMENTED

If a is a zero of a polynomial f(x)

Then by the Remainder Theorem the Remainder

$f(a) = 0$

TO DETERMINE

one zero of the quadratic polynomial

$(k-1){x}^{2} + kx + 1$ is - 3

then to determine value of k

CALCULATION

Let

$f(x) = (k-1){x}^{2} + kx + 1$

Since - 3 is a zero of the polynomial

So by the Remainder Theorem

$f(-3) =0$

$\implies \: (k-1){(-3)}^{2} + k(-3) + 1=0$

$\implies \: 9(k-1)-3k+1 = 0$

$\implies \: 9k-9-3k+1 = 0$

$\implies \: 6k=8$

$\therefore k=\frac{4}{3}$

Answer 2

Answer:

THE CORRECT OPTION IS A. THAT IS 4/3

Step-by-step explanation:

HAVE A NICE DAY.... THANKS DEAR..