If one of the zeroes of the quadratic polynomial (k-1)x²+kx+1 is 3 then find the value of k how many zeroes can quadratic polynomial have
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Substitute 3 in equation
(K-1)×9+3k+1=0
9k-9+3k+1=0
12k-8=0
k=2/3
Quadratic can have only 2 zeros
In any polynomial the highest power to which x is raised gives the number of zeros/roots of equation.
I hope it will help!!!
(K-1)×9+3k+1=0
9k-9+3k+1=0
12k-8=0
k=2/3
Quadratic can have only 2 zeros
In any polynomial the highest power to which x is raised gives the number of zeros/roots of equation.
I hope it will help!!!
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5
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