Question

If one of the zeroes of the quadratic polynomial(k-1)x²+kx+1 is -3, then value

of k is​

Answer 1

Answer:

P(x) = (k – 1)x2 + kx +1

P(1) = (k – 1)12 + k +1 = 0

k-1 + k + 1 = 0

2k = 0

k = 0

Answer 2

Answer:

k = 4/3

Step-by-step explanation:

X=-3(Given)

(k-1)x^2+ke+1=0

(k-1)(-3)^2+k(-3)+1=0

(k-1)(9)-3k+1=0

9k-9-3k+1=0

6k-8=0

6k=8

k=8/6

k=4/3