Question

If one of the zeroes of the quadratic polynomial (k-1)x2+kx+1 is '-3' then the value of 'k' is​

Answer 1

Answer:

k = 4/3

Step-by-step explanation:

==: (k - 1)x²  + kx + 1 = 0

-3 is zero of this poynomial

==: (k - 1)(-3)² + k(-3) + 1 = 0

==: (k - 1) 9 - 3k + 1 = 0

==: 9k - 9 - 3k + 1 = 0

==: 6k - 8 = 0

==: k = 4/3

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Answer 2

Answer:

k = 1/5

Step-by-step explanation:

p(x) = (k-1) * 2 + kx + 1 =0

p(3) = (k-1) * 2 +3k + 1 = 0

      => 2k - 2 + 3k +1 = 0

           5k -1 = 0

           5k = 1

          k = 1/5