Question

if one of the zeroes of the quadratic polynomial (k-1)x2+kx+1 is 3,find k.

Answer 1

f(3)=f(x)=0( reminder theoram)
=> (k-1)*3^2+k*3+1=0
=> 9k-9+3k+1=0
=> 12k-8=0
=> k=0.66667=2/3 Answer
Thank u Hope it helped u!

Answer 2

Step-by-step explanation:

GIVEN:-)

→ One zeros of quadratic polynomial = -3.

→ Quadratic polynomial = ( k - 1 )x² + kx + 1.

Solution:-

→ P(x) = ( k -1 )x² + kx + 1 = 0.

→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.

=> ( k - 1 ) × 9 -3k + 1 = 0.

=> 9k - 9 -3k + 1 = 0.

=> 6k - 8 = 0.

=> 6k = 8.

$\large \boxed{=> k = \frac{8}{6} = \frac{4}{3} }$

Hence, the value of ‘k’ is founded .