Question

if one of the zeroes of the quadratic polynomial (k-1)x2+kx+1is -3,then the value of k​

Answer 1

Answer:

4/3

Step-by-step explanation:

Let, f(x) = (k-1)x^2 + kx + 1

Since, -3 is a zero if the given polynomial, Therefore f(-3) = 0

So, f(-3) = (k-1)(-3)^2 + k(-3) + 1 = 0

9(k-1) - 3k + 1 = 0

9k - 9 - 3k + 1 = 0

6k - 8 = 0

So k = 4/3

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Answer 2

$f(x) = (k - 1)x² + kx + 1$

$f(3) = 0$

$(k - 1) × (3)² + (-3)k + 1 = 0$

$(k - 1)9 - 3k + 1 = 0$

$9k - 9 - 3k + 1 = 0$

$6k - 8 = 0$

$6k = 8$

$k = \frac{8}{6}$

$k = \frac{4}{3}$