Question

If one of the zeroes of the quadratic polynomial (K-1)x2

- Kx + 3 is -3 then

find the value of K​

Answer 1

Given :-

One of the zeros of the quadratic polynomial

(k - 1)x² - Kx + 3 is (-3)

So,

• x = -3

To FinD :-

• The value of k is ?

Solution :-

$: \implies \: x = - 3$

Putting the value of x into polynomial →

$: \implies(k - 1) {x}^{2} - kx + 3 = 0 \\ \\ : \implies \: (k - 1) \times ( { - 3)}^{2} - k \times ( - 3) + 3 = 0 \\ \\ : \implies(k - 1) \times 9 + 3k + 3 = 0 \\ \\ : \implies \: 9k - 9 + 3k + 3 = 0 \\ \\ : \implies12k - 6 = 0 \\ \\ : \implies12k = 6 \\ \\ : \implies \: k = \frac{6}{12} \\ \\ : \implies \: k = \frac{1}{2}$

Hence , the value of k is 1/2