Question

If one of the zeroes of the quadratic polynomial (k-2)x² + kx + 1 is (-2), then find the value​

Answer 1

Answer:

7/2

Step-by-step explanation:

(k–2)x² + kx +1

ONE OF ZEROES IS GIVEN (–2)

i.e. x = –2.

PUT VALUE OF X IN GIVEN POLYNOMIAL WE GET THAT ,

(k–2)(–2)² + k(–2) + 1

4(k–2) – 2k +1 =0

4k –8 –2k +1 =0

2k –7 =0

2k = 7

k=7/2.

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