if one of the zeroes of the quadratic polynomial p-1 x^2+px+1 is -3, then find value of p
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Step-by-step explanation:
X^2+pX+1=0
p(X)=x^2 +px+1 =0
p(3)= (3)^2+p(3)+1
=(3*3)+3p+1=0. [it can be equated to zero since 3 is the zero of the polynomial ]
=9+3p+1=0
10+3p=0
3p= -10
p= -10/3
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