Math, asked by afsase14, 11 months ago

if one of the zeroes of the quadratic polynomial p-1 x^2+px+1 is -3, then find value of p

Answers

Answered by thotosatyanaryana50
3

Step-by-step explanation:

X^2+pX+1=0

p(X)=x^2 +px+1 =0

p(3)= (3)^2+p(3)+1

=(3*3)+3p+1=0. [it can be equated to zero since 3 is the zero of the polynomial ]

=9+3p+1=0

10+3p=0

3p= -10

p= -10/3

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