Question

If one of the zeroes of the quadratic polynomial p-1 x^2+px+1 is -3, then find value of p

Answer 1

the correct

value of p is 4/3.

Answer 2

Given:

             One of the zeroes of polynomial = -3

To Find:

             The value of p

Solution:

By the property of the quadratic equation,

Putting the given zero of the quadratic polynomial in the given equation, i.e.

                                          $(p-1)x^2+px+1$

After putting the value in the equation, the equation must be equal to zero.

So, by solving the given equation,

                                 $(p-1)(3)^2+p(3)+1=0\\(p-1)9+3p+1=0\\9p-9+3p+1=0\\12p-8=0\\12p=8$

the value of p comes to be,

                                  $p=\frac{12}{8}$

Hence the value of p is  $\frac{12}{8}$