Question

If one of the zeroes of the quadratic polynomial (p – l)x² + px + 1 is -3, then the value of p is​

Answer 1

Answer:

3.3 bar

step by step explanation :-

x^2 + px + 1 = 0 ( x = -3 )

(-3) ^2 + p ( -3 ) + 1 = 0

9 + ( -3p ) + 1 = 0

10 - 3p = 0

10 = 3p

P = 3.3 bar

hope this is helpful for you

Answer 2

Answer:

Step-by-step explanation:

First we put the value of X in (p-1)x²+px+1

:. (p-1)(-3)²+(-3p)+1=0

-9p²+9-3p+1=0

-9p²-3p+10=0

-9p²+9p-10p+10=0

-9p(p+1)-10(p+1)

(-9p-10)(p+1)=0

P= -10/9. Or p=1