Question

If one of the Zeroes of the quadratic polynomials (a-1)x+ ax+1is -3, then find the value of a. please answer quick and dont spam​

Answer 1

answer and explanation in the picture

Answer 2

Step-by-step explanation:

Given:

*Correct quadratic polynomial may be

$(a -1 ) {x}^{2} + ax + 1$

To find: Value of a,if one of the zero of quadratic polynomial is -3.

Solution:

If one zero is -3,that is x= -3 satisfy the quadratic equation.

Put the value

$(a - 1) {x}^{2} + ax + 1 = 0 \\ \\ (a - 1)( - 3)^{2} + a( - 3) + 1 = 0 \\ \\ 9(a - 1) - 3a + 1 = 0 \\ \\ 9a - 9 - 3a + 1 = 0 \\ \\ 6a - 8 = 0 \\ \\ a = \frac{8}{6} \\ \\ a = \frac{4}{3}$

Final answer:

$\bold{a = \frac{4}{3} }$

Hope it helps you.

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