Math, asked by theis9911, 2 months ago

If one of the Zeroes of the quadratic polynomials (a-1)x+ ax+1is -3, then find the value of a​

Answers

Answered by surendernitu123
0

since one root is -3 if we put value of a as -1 then we get the root as zero then when we equate to 0 we get a=5

hoping you like the answer mark me

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Answered by hukam0685
1

Step-by-step explanation:

Given:

*Correct quadratic polynomial may be

(a -1 ) {x}^{2}  + ax + 1  \\

To find: Value of a,if one of the zero of quadratic polynomial is -3.

Solution:

If one zero is -3,that is x= -3 satisfy the quadratic equation.

Put the value

(a - 1) {x}^{2}  + ax + 1 = 0 \\  \\ (a - 1)( - 3)^{2}  + a( - 3) + 1 = 0 \\  \\ 9(a - 1) - 3a + 1 = 0 \\  \\ 9a - 9 - 3a + 1 = 0 \\  \\ 6a - 8 = 0 \\  \\ a =  \frac{8}{6}  \\  \\ a =  \frac{4}{3}  \\  \\

Final answer:

\bold{a =  \frac{4}{3} } \\  \\

Hope it helps you.

To learn more on brainly:

Given that the zeroes of the cubic polynomial

x³– 15x²+ 66x – 80 are of the form a, a + b, a + 2b for some p...

https://brainly.in/question/18132288

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