if one of the zeroes of the quadratic polynomials (k-1)x^2 + 1 is 2 ,then the value of k is
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if one of the zeroes of the quadratic polynomials (k-1)x^2 + 1 is 2 ,then the value of k is→ One zeros of quadratic polynomial = -3.
→ Quadratic polynomial = ( k - 1 )x² + kx + 1.
Solution:-
→ P(x) = ( k -1 )x² + kx + 1 = 0.
→ p(-3) = ( k - 1 )(-3)² + k(-3) + 1 = 0.
=> ( k - 1 ) × 9 -3k + 1 = 0.
=> 9k - 9 -3k + 1 = 0.
=> 6k - 8 = 0.
=> 6k = 8.
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