Question

If one of the zeroes of the quadtatic Polynomial
${k - 1}x {?}^{2 + kx + 1is - 3}$
then the value of k is​

Answer 1

Answer:

Given −3 is the zero of the polynomial (k−1)x 2 +kx+1

So −3 must satisfy the equation(k−1)x+kx+1=0

⟹(k−1)(−3) 2 +k(−3)+1=0

⟹9(k−1)−3k+1=0

⟹9k−9−3k+1=0

⟹6k=8

⟹k= 3

4