Question

If one of the zeroes of the quardratic polynomial (k-1) x 2 + kx is -3 then the value of k is ?

Answer 1

Answer :-

k = 3/2

Solution :-

Let p( x ) = ( k - 1 )x² + kx

Zero of the polynomial is - 3

We know that

Zero of the polynomial is the value of x for which the polynomial value is 0

⇒ p( - 3 ) = 0

⇒ ( k - 1 )( - 3 )² + k( - 3 ) = 0

⇒ ( k - 1 )( 9 ) - 3k = 0

⇒ 9k - 9 - 3k = 0

⇒ 6k - 9 = 0

⇒ 6k = 9

⇒ k = 9/6

⇒ k = 3/2

Therefore the value of k is 3/2.

Answer 2

QUESTION

If one of the zeroes of the quadratic polynomial

$(k - 1) {x}^{2} + kx$

is -3 then the value of k is:

SOLUTION

Since -3 is a zero of given quadratic polynomial then if we will put -3 in place of x in the polynomial then it should be equal to zero.

hence,

$(k - 1) {( - 3)}^{2} + k( - 3) = 0 \\ \\ (k - 1)(9) - 3k = 0 \\ \\ 9k - 9 - 3k = 0 \\ \\ 6k - 9 = 0 \\ \\ 6k = 9 \\ \\ k = \frac{9}{6} \\ \\ k = \frac{3}{2}$

SO THE VALUE OF 'k' IS 3/2 .