Question

if one of the zeroes of the quardratic polynomial (k-1)x2+kx+1 is -3,then the value of k

Answer 1

Here p(x)=(k-1)x^2+kx+1
acoording to question x=-3
putting the value of x in p(x)
we get
kx^2-x^2+kx+1
=9k-9-3k+1
=-6k-8
then k=8/6
k=4/3.
hope my ans helped you.

Answer 2

Here we have one of the root as -3 so simply put x=-3 in the given equation and equate the equal to zero.

$(k - 1)( { - 3}^{2} ) + (k)( - 3) + 1 = 0$

$9k - 9 - 3k + 1 = 0$


$6k = 8$

so k=4/3