if one of the zeroes of the qudratic polynomial is ( k - 1 ) x square + kx +1 is -3 . Then find the value of k
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(k-1)x²+kx+1=0
(k-1)(-3)²+k(-3)+1=0
(k-1)(9)- 3k+1=0
9k- 9- 3k+1=0
9k-3k=9-1
6k=8
k=8/6
implies, k=4/3
hope it helps.......
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(k-1)(-3)²+k(-3)+1=0
(k-1)(9)- 3k+1=0
9k- 9- 3k+1=0
9k-3k=9-1
6k=8
k=8/6
implies, k=4/3
hope it helps.......
please mark it brainliest if it helped you
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