Math, asked by hirdyansharya1, 2 months ago

If one of the zeros of 2x² + ax + 3 is 1, find the other zero and the value
of a​

Answers

Answered by BlazeBlazing
0

Answer:-

  • 2x² + ax + 3
  • putting zero of the polynomial
  • p(1)= 2(1)² + a(1) + 3
  • evaluation gives a=-5
  • now the other zero of the polynomial =
  • 2x² + ax + 3 =
  • 2x² + -5x + 3=0
  • 2x² +-2x-3x + 3=0
  • 2x (x-1) -3 (x-1)
  • therefore (2x -3)(x-1)
  • x=3/2 is the other zero

Answered by muskansangrey
0

Answer:

2(1) ^2 + a ×1 +3 =0

2+a+3=0

5+a=0

a =-5

2x^2 -5x +3 =

2x^2 -2x-3x +3=0

2x(x-1) -3(x-1) =0

(2x-3) (x-1) =0

2x-3=0, x-1=0

2x=3 , x=1

x=3/2 , x=1 ans

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