Question

if one of the zeros of a cubic polynomial X^3+ax^2+c is -1, then what is the product of othe two zeros?​

Answer 1

Answer:

By relation, we know,

product of all zeroes of a cubic equation= -c/a

a = 1 (since coefficient of x^3 is 1)

let other two zeroes be x and y

then,

(-1)*x*y= -c

hence, x*y = c