If one of the zeros of cubic polynomial is -1 the polynomial x cube + x square + bx + c then the product of other two zeros is
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Hey
As we know product of the three zeros in a polynomial is -d/a
α×β×Φ = -d ÷ a
Since one zero is -1 it'll be
-1*β*Φ = -c/1
Which implies the product of the other two zeroes is c
pranju86:
hiii nandini
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let the other two zeroes of this polynomial be m and n. then, product of zeroes =-c/a . so, the product of two zeroes is equal to c
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