if one of the zeros of polynomial ( a square + 9 ) X square + 13 x + 6 a is reciprocal of the Other of other find the value of a
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(a2+9)x2+13x+6a=0
product of roots of quadratic equation in the form, ax2+bx+c=0 is c/a
product of roots(in this case, reciprocals)=1
(6a)/(a2+9)=1
6a=a2+9
a2-6a+9=0
(a-3)2=0
a-3=0
a=3
product of roots of quadratic equation in the form, ax2+bx+c=0 is c/a
product of roots(in this case, reciprocals)=1
(6a)/(a2+9)=1
6a=a2+9
a2-6a+9=0
(a-3)2=0
a-3=0
a=3
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0
Answer:
the answer is 3
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